Reaction Mechanisms -- Practice Problems
Reaction Mechanisms — Practice Problems
10 MCQ questions covering SN1/SN2, E1/E2, electrophilic aromatic substitution, and carbocation chemistry. Select an option to check your answer and view the explanation.
Worked Examples
Example 1: Predicting SN1 vs SN2, Decision Tree
Problem: For each reaction, predict the mechanism and major product:
(a) 1-bromobutane + NaOEt in EtOH (b) 2-bromo-2-methylpropane + H₂O (c) (R)-2-bromopentane + NaCN in DMSO
Solution:
(a) Primary substrate + strong nucleophile + polar protic solvent → SN2
Product: 1-ethoxybutane (inversion at primary carbon, but primary carbons are not stereogenic)
(b) Tertiary substrate + weak nucleophile + polar protic solvent → SN1
Product: 2-methyl-2-propanol (racemic if stereogenic, but this substrate is achiral)
(c) Secondary substrate + strong nucleophile + polar aprotic solvent → SN2
Product: (S)-2-cyanopentane (inversion of configuration from R to S)
Decision summary:
| Factor | SN2 | SN1 |
|---|---|---|
| Substrate | ||
| Nucleophile | Strong (⁻OH, ⁻CN, ⁻OR) | Weak (H₂O, ROH) |
| Solvent | Polar aprotic (DMSO, DMF) | Polar protic (H₂O, ROH) |
| Stereochemistry | Inversion | Racemization |
| Kinetics | Second-order: | First-order: |
Example 2: E2 Elimination, Regioselectivity
Problem: Predict the major product of E2 elimination for 2-bromo-2-methylbutane with (a) NaOEt and (b) KOtBu.
Solution:
The substrate has two types of β-hydrogens:
- C1 hydrogens (3 H’s) → less substituted alkene (Hofmann)
- C3 hydrogens (2 H’s) → more substituted alkene (Zaitsev)
(a) NaOEt (small base): Favors Zaitsev product (more substituted, more stable)
Major product: 2-methyl-2-butene (trisubstituted alkene)
(b) KOtBu (bulky base): Favors Hofmann product (less substituted, less steric hindrance)
Major product: 2-methyl-1-butene (disubstituted alkene)
Key insight: The base size controls regioselectivity. Small bases approach the more substituted β-hydrogen (Zaitsev). Bulky bases are sterically hindered and abstract the more accessible β-hydrogen (Hofmann).
Example 3: Carbocation Rearrangement
Problem: When 3,3-dimethyl-2-butanol is treated with H₂SO₄, what is the major product?
Solution:
Step 1: Protonation of the hydroxyl group
Step 2: Loss of water → secondary carbocation
Step 3: 1,2-methyl shift → tertiary carbocation (more stable)
Step 4: Elimination → tetrasubstituted alkene (most stable)
Key insight: Carbocation rearrangements occur when a more stable carbocation can be formed. The driving force is the stability order: . Always check for possible rearrangements in SN1 and E1 reactions.
Nucleophilic Substitution and Elimination
Electrophilic Reactions and Rearrangements
Intuition
Reaction mechanisms are the “stories” of how bonds break and form: Every organic reaction has a mechanism, a step-by-step sequence of electron movements shown with curly arrows. Understanding mechanisms lets you predict products of reactions you have never seen before.
Why it matters: Mechanistic reasoning is how pharmaceutical companies design drug syntheses, how chemists troubleshoot failed reactions, and how new catalysts are developed.
The key insight: SN1 vs SN2, E1 vs E2, the competition between substitution and elimination is governed by the same factors: substrate structure, nucleophile strength, solvent polarity, and temperature.
Common Mistakes
Confusing SN1 and SN2 mechanisms: SN2 is a one-step, backside attack with inversion of configuration and second-order kinetics. SN1 is a two-step mechanism with a carbocation intermediate, racemisation, and first-order kinetics. The substrate (primary/secondary/tertiary), nucleophile strength, and solvent polarity determine which pathway dominates. Do not assume one mechanism applies to all substrates.
Ignoring stereochemistry in elimination reactions: E2 elimination requires an anti-periplanar arrangement of the leaving group and the -hydrogen. This stereoelectronic requirement determines which product forms (Zaitsev vs Hofmann). Failing to check the anti-periplanar geometry leads to predicting the wrong alkene product.
Confusing kinetic and thermodynamic enolates: The kinetic enolates form faster (less substituted, using a strong base at low temperature), while the thermodynamic enolates are more stable (more substituted, using a weaker base at higher temperature). The conditions determine which enolates forms, which in turn determines the alkylation product.
Cross-References
- Reaction Mechanisms: Detailed notes on , , E1, and E2 mechanisms.
- Structure and Bonding: Covers molecular orbital theory and stereochemistry concepts.
- Practice Spectroscopy and Synthesis: Interactive practice problems covering NMR, IR, and multi-step synthesis.